2x^2+x(3-k)-7=0

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Solution for 2x^2+x(3-k)-7=0 equation:


Simplifying
2x2 + x(3 + -1k) + -7 = 0
2x2 + (3 * x + -1k * x) + -7 = 0

Reorder the terms:
2x2 + (-1kx + 3x) + -7 = 0
2x2 + (-1kx + 3x) + -7 = 0

Reorder the terms:
-7 + -1kx + 3x + 2x2 = 0

Solving
-7 + -1kx + 3x + 2x2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + -1kx + 3x + 7 + 2x2 = 0 + 7

Reorder the terms:
-7 + 7 + -1kx + 3x + 2x2 = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -1kx + 3x + 2x2 = 0 + 7
-1kx + 3x + 2x2 = 0 + 7

Combine like terms: 0 + 7 = 7
-1kx + 3x + 2x2 = 7

Add '-3x' to each side of the equation.
-1kx + 3x + -3x + 2x2 = 7 + -3x

Combine like terms: 3x + -3x = 0
-1kx + 0 + 2x2 = 7 + -3x
-1kx + 2x2 = 7 + -3x

Add '-2x2' to each side of the equation.
-1kx + 2x2 + -2x2 = 7 + -3x + -2x2

Combine like terms: 2x2 + -2x2 = 0
-1kx + 0 = 7 + -3x + -2x2
-1kx = 7 + -3x + -2x2

Divide each side by '-1x'.
k = -7x-1 + 3 + 2x

Simplifying
k = -7x-1 + 3 + 2x

Reorder the terms:
k = 3 + -7x-1 + 2x

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